std::literals::chrono_literals::operator""us

 

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std::chrono::duration

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Defined in header <chrono>
constexpr std::chrono::microseconds operator "" us(unsigned long long us);	(1)	(since C++14)
constexpr std::chrono::duration</*unspecified*/,                            std::micro> operator "" us(long double us);	(2)	(since C++14)

Forms a std::chrono::duration literal representing microseconds.

1) integer literal, returns exactly std::chrono::microseconds(us)

2) floating-point literal, returns a floating-point duration equivalent to std::chrono::microseconds

Parameters

us

-

the number of microseconds

Return value

The std::chrono::duration literal.

Possible implementation

constexpr std::chrono::microseconds operator ""us(unsigned long long us) { return std::chrono::microseconds(us); } constexpr std::chrono::duration<long double, std::micro> operator ""us(long double us) { return std::chrono::duration<long double, std::micro>(us); }

Notes

These operators are declared in the namespace std::literals::chrono_literals, where both literals and chrono_literals are inline namespaces. Access to these operators can be gained with using namespace std::literals, using namespace std::chrono_literals, and using namespace std::literals::chrono_literals.

In addition, within the namespace std::chrono, the directive using namespace literals::chrono_literals; is provided by the standard library, so that if a programmer uses using namespace std::chrono; to gain access to the duration classes, the duration literal operators become visible as well.

Example

Run this code

#include <iostream>
#include <chrono>
 
int main()
{
    using namespace std::chrono_literals;
    auto d1 = 250us;
    std::chrono::microseconds d2 = 1ms;
    std::cout << "250us = " << d1.count() << " microseconds\n"
              << "1ms = " << d2.count() << " microseconds\n";
}

Output:

250us = 250 microseconds
1ms = 1000 microseconds

See also

(constructor)

constructs new duration (public member function of std::chrono::duration)